Rs Aggarwal %282017%29 Solutions for Class 8 Math Chapter 10 Profit And Loss are provided here with simple step-by-step explanations. These solutions for Profit And Loss are extremely popular among Class 8 students for Math Profit And Loss Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal %282017%29 Book of Class 8 Math Chapter 10 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal %282017%29 Solutions. All Rs Aggarwal %282017%29 Solutions for class Class 8 Math are prepared by experts and are 100% accurate. Show
Page No 134:Question 1:Find the gain or loss per cent when: Answer:(i)CP=Rs. 620 SP=Rs. 713Since SP> CP, there is a gain.Gain =713 - 620 = Rs. 93Gain percentage=(gainCP×100)% = (93620×100)% =15% (ii) (iii) (iv) Page No 134:Question 2:Find the selling price when: Answer:(i) (ii) (iii) (iv) CP=Rs. 645Loss percentage=13 13%=403%SP=(100-loss %)100×CP=(100-403)100 ×645=300-403100×645=2603×1100×645=Rs . 559 Page No 134:Question 3:Find the cost price when: Answer:(i)SP=Rs. 1596Gain percentage=12%CP=100(100+gain %)×SP=100(100+12)×1596=Rs. 1425 (ii) SP= Rs. 2431 Loss percentage=612%=132%CP=100(100-loss %)×SP =100(100-132)×2431=100×2187×2431=Rs. 2600 (iii) (iv) Page No 134:Question 4:Manjit bought an iron safe for ₹ 12160 and paid ₹ 340 for its transportation. Then, he sold it for ₹ 12875. Find his gain per cent Answer:CP of the iron safe = ₹12,160 Page No 134:Question 5:Robin purchased an old car for Rs 73500. He spent Rs 10300 on repairs and paid Rs 2600 for its insurance. Then he sold it to a mechanic for Rs 84240. What was his percentage gain or loss? Answer:
Page No 134:Question 6:Hari bought 20 kg of rice at ₹ 36 per kg and 25 kg of rice at ₹ 32 per kg. He mixed the two varieties and sold the mixture at ₹ 38 per kg. Find his gain per cent in the whole transaction. Answer:Total cost of rice of 1st variety = ₹36/kg × 20 kg = ₹720 Page No 134:Question 7:Coffee costing Rs 250 per kg was mixed with chicory costing Rs 75 per kg in the ratio 5 : 2 for a certain blend. If the mixture was sold at Rs 230 per kg, find the gain or loss per cent. Answer:Let 5 kg of coffee be mixed with 2 kg of chicory.CP of the mixture= Rs (250×5+75×2)=Rs (1250+150)=Rs. 1400SP of the mixture=Rs (7×230)=Rs. 1610Since SP>CP, there is a gain. Now, gain=Rs (1610-1400)=Rs. 210Gain percentage=(gaintotal CP×100)%=(2101400× 100)%=15% Page No 134:Question 8:If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain per cent earned by the dealer. Answer:Let Rs x be the SP of each bottle and Rs y be the CP of each bottle .SP of 16 bottles = CP of 17 bottles⇒16x=17y⇒x y=1716Gain per bottle=SP-CP=Rs (x-y)∴ Gain percentage =(gainCP×100)%=(x-yy×100)%={(xy-1 )×100}%={(1716-1)×100}%=(116×100)%=614% Page No 134:Question 9:The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss per cent. Answer:Let Rs x be the CP of one candle and Rs . y be the SP of one candle.Now, CP of 12 candles=SP of 15 candles⇒12x=15y⇒yx=1215Loss = CP-SP=Rs (x-y) ∴ Loss percentage=(lossCP×100)%={(x-yx)×100}%={(1-yx) ×100}%={(1-1215)×100}%=(315×100)%=20% Page No 134:Question 10:By selling 130 cassettes, a man gains an amount equal to the selling price of 5 cassettes. Find the gain per cent. Answer:It is given that, Page No 134:Question 11:By selling 45 lemons, a vendor loses a sum equal to the selling price of 3 lemons. Find his loss per cent. Answer:Let Rs x be the SP of one lemon.SP of 45 lemons=Rs. 45xLoss=SP of 3 lemons=Rs. 3x But loss=CP-SPCP=loss+SP=3x+45x=Rs. 48x∴ Loss percentage=(lossCP×100)%=(3x48x×100)%=614% Page No 134:Question 12:Oranges are bought at 6 for ₹ 20 and sold at 4 for ₹ 18. Find the gain or loss per cent. Answer:LCM of 6 and 4 = 12 Page No 134:Question 13:A vendor purchased bananas at ₹ 40 per dozen and sold them at 10 for ₹ 36. Find his gain or loss per cent. Answer:LCM of
12 and 10 = 60 Page No 134:Question 14:A man bought apples at 10 for ₹ 75 and sold them at ₹ 75 per dozen. Find his loss per cent. Answer:LCM of 10 and 12 = 60 Page No 134:Question 15:A man purchased some eggs at 3 for ₹ 16 and sold them at 5 for ₹ 36. Thus, he gained ₹ 168 in all. How many eggs did he purchase? Answer:Let the number of eggs purchased be x. Page No 135:Question 16:A dealer sold a camera for Rs 1080 gaining 18 of its cost price. Find (i) the cost price of the camera, and (ii) the gain per cent earned by the dealer. Answer:SP of the camera=Rs. 1080Let Rs x be the CP.Gain=Rs. 18x ...(i)Also, gain=SP-CP =Rs. ( 1080 -x) ...(ii)From (i) and (ii), we have: 18x=1080 -x⇒x=8640-8x⇒9x=8640⇒x=960∴ CP=Rs . 960Now, gain =18x=9608=Rs. 120∴ Gain percentage =(120960×100)%=1212% Page No 135:Question 17:Meenakshi sells a pen for Rs 54 and loses 110 of her outlay. Find (i) the cost price of the pen, and (ii) the loss per cent. Answer:SP of the pen=Rs. 54Let Rs x be the CP of the pen. Loss=Rs. x10SP=CP-Loss =x-x10 =Rs. 9x10Now, we have9x10=54⇒x=54×109⇒ x=60∴ CP of the pen=Rs. 60Now, loss=x10 =6010 =Rs. 6∴ Loss percentage=(lossCP×100)%=(660×100)%=10% Page No 135:Question 18:A dealer gets ₹ 940 more if instead of selling a table at a loss of 10%, it is sold at a gain of 10%. Find the cost price of the table. Answer:Let the cost price be ₹x. Page No 135:Question 19:A dealer gets Rs 56 less if instead of selling a chair at a gain of 15%, it is sold at a gain of 8%. Find the cost price of the chair. Answer:Let Rs x be the CP.Gain1 percentage=gain1CP ×100%⇒15=gain1x×100⇒Gain1=Rs 15x100Again, gain2 percentage=gain2CP×100%⇒8=gain2x×100⇒Gain2=Rs 8x100 According to the question, we have:Gain1-gain 2= 56⇒15x 100 - 8x100=56⇒7x100=56⇒7x=5600⇒x=800Hence, the CP of the chair is Rs 800. Page No 135:Question 20:A cycle was sold at a gain of 10%. Had it been sold for ₹ 260 more, the gain would have been 14%. Find the cost price of the cycle. Answer:Let the CP be ₹x. Page No 135:Question 21:Sonu buys 40 kg of wheat at ₹ 12.50 per kg and 30 kg of wheat at ₹ 14 per kg. At what rate per kg should he sell the mixture to gain 5% on the whole? Answer:40 kg of wheat is bought for ₹12.50/kg. Page No 135:Question 22:Wasim bought two cricket bats for ₹ 840 and ₹ 360 respectively. He sells the first bat at a gain of 15% and the second one at a loss of 5%. Find his gain or loss per cent in the whole transaction. Answer:CP of the first bat = ₹840 Page No 135:Question 23:Hema bought two pairs of jeans for ₹ 1450 each. She sold one of them at a gain of 8% and the other at a loss of 4%. Find her gain or loss per cent in the whole transaction. Answer:CP of first jeans = ₹1,450 Page No 135:Question 24:A grocer purchased 200 kg of rice at Rs 25 per kg. He sold 80 kg of it at a gain of 10% and 40 kg at a loss of 4%. At what rate per kg should he sell the remainder to gain 8% on his total investment? Answer:CP of 1 kg of rice = Rs 25 CP of 40 kg of rice = Rs (25×40)=Rs 1000 SP of 80 kg of rice = 100+gain% 100×CP=Rs 110100×2000=Rs 2200 SP of 40 kg rice=100-loss %100×CP=Rs 96100×1000=Rs 960 SP of 200 kg rice=100 +gain%100×CP=Rs 108100×5000=Rs 5400 Remaining quantity of rice = (200 − 80 + 40) kg = 80 kg SP of the remaining rice (80 kg) = Rs (5400 − 2200 − 960) ∴ Rate per kg = Rs 224080= Rs 28 Page No 135:Question 25:If the selling price of a TV set is equal to 65 of its cost price, find the gain per cent. Answer:Let the CP of the TV set be ₹x. Page No 135:Question 26:If the selling price of a flower vase is 56 of its cost price, find the loss per cent. Answer:Let the CP of the flower vase set be ₹x. Page No 135:Question 27:By selling a bouquet for Rs 322, a florist gains 15%. At what price should he sell it to gain 25%? Answer:SP of the bouquet = Rs 322 Now, CP = Rs 128 and desired gain percentage = 25% ∴ Desired SP=100+gain%100 ×CP=Rs 125100×280=Rs 350 Hence, the selling price to obtain the desired gain must be Rs 350. Page No 135:Question 28:By selling an umbrella for ₹ 336, a shopkeeper loses 4%. At what price must he sell it to gain 4%? Answer:Let the CP of the umbrella be ₹x. Page No 135:Question 29:A radio is sold for Rs 3120 at a loss of 4%. What will be the gain or loss per cent if it is sold for Rs 3445? Answer:Let the original price be x. So, the cost price is Rs 3250. If it is sold for Rs 3445, then its a gain because SP > CP. Hence, gain percent = 6% Page No 135:Question 30:Luxmi sold two sarees for ₹ 1980 each. On one, she lost 10%, while on the other she gained 10%. Find her gain or loss per cent in the whole transaction. Answer:SP of first saree = ₹1,980 Page No 135:Question 31:A shopkeeper sold two fans for ₹ 1140 each. On one he gains 14%, while on the other he loses 5%. Calculate his gain or loss per cent in the whole transaction. Answer:SP of first fan = ₹1,140 Page No 135:Question 32:Vinod sold a watch to Arun at a gain of 12% and Arun had to sell it to Manoj at a loss of 5%. If manoj paid ₹ 3990 for it, how much did vinod pay for the watch? Answer:Let the CP of the watch for Vinod be ₹x. Page No 135:Question 33:Ahmed buys a plot of land for ₹ 480000. He sells of it at a loss of 6%. At what gain per cent should he sell the remaining part of the plot to gain 10% on the whole? Answer:CP of the plot of land = ₹4,80,000 Page No 135:Question 34:A grocer bought sugar worth Rs 4500. He sold one-third of it at a gain of 10%. At what gain per cent must the remaining sugar be sold to have a gain of 12% on the whole? Answer:CP of sugar = Rs 4500 CP of one-third of the sugar = Rs 45003=Rs. 1500 SP of one-third of the sugar =100+gain%100×CP=Rs 110100×1500=Rs 1650 Now, profit= Rs (1650 − 1500) = Rs 150 At a profit of 12%, we have: ∴ Gain= Rs (5040 − 4500) = Rs 5400 Profit on the remaining amount of sugar = Rs (540 − 150) = Rs 390 Gain percentage=gainCP×100% =3903000×100% = 13% Therefore, the profit on the remaining amount of sugar is 13%. Page No 138:Question 1:The marked price of a water cooler is Rs 4650. The shopkeeper offers an off-season discount of 18% on it. Find its selling price. Answer:Marked price = Rs 4650 and discount = 18% Therefore, the selling price of the cooler is Rs 3813. Page No 138:Question 2:The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season. Find the rate of discount given by him. Answer:Marked Price = Rs 960 Therefore, the discount on the sweater is 15%. Page No 138:Question 3:Find the rate of discount being given on a shirt whose selling price is ₹ 1092 after deducting a discount of ₹ 208 on its marked price. Answer:SP of the shirt = ₹1,092 Page No 138:Question 4:After allowing a discount of 8% on a toy, it is sold for Rs 216.20. Find the marked price of the toy. Answer:Selling Price = Rs 216.20 Now, x-8100×x=216.20⇒92x100=216.20⇒92x=21620⇒x =2162092⇒x=235 ∴ Marked price = Rs 235 Page No 138:Question 5:A tea set was bought for Rs 528 after getting a discount of 12% on its marked price. Find the marked price of the tea set. Answer:
Cost price = Rs 528 Therefore, the marked price of tea set is Rs 600. Page No 138:Question 6:A dealer marks his goods at 35% above the cost price and allows a discount of 20% on the marked price. Find the gain or loss per cent. Answer:Let Rs 100 be the CP. ∴ Gain percentage=gainCP×100 = 8100×100= 8% Page No 138:Question 7:A cellphone was marked at 40% above the cost price and a discount of 30% was given on its marked price. Find the gain or loss per cent made by the shopkeeper. Answer:Let Rs 100 be the CP. Therefore, the shopkeeper had a loss of 2%. Page No 138:Question 8:A dealer purchased a fan for Rs 1080. After allowing a discount of 25% on its marked price, he gains 25%. Find the marked price of the fan. Answer:Cost price of the fan = Rs 1080 Let the marked price be Rs x. =25x100 SP = MP − discount ⇒1350=100x-25x100⇒135000=75x⇒x=1350075⇒x=1800 Therefore, the marked price of the fan is Rs 1800. Page No 138:Question 9:A dealer bought a refrigerator for Rs 11515. After allowing a discount of 16% on its marked price, he gains 20%. Find the marked price of the refrigerator.
Answer:Cost price of the refrigerator = Rs 11515 Let the marked price be Rs x. ⇒13818=100x-16x100⇒1381800=84x ⇒x=138180084⇒x=16450 Therefore, the marked price of the refrigerator is Rs 16450. Page No 138:Question 10:A jeweller allows a discount of 16% to his customers and still gains 20%. Find the marked price of a ring which costs the jeweller Rs 1190. Answer:The cost price of the ring is Rs 1190. Let the marked price be x. ⇒1428=x-16x100⇒1428= 100x-16x100⇒142800=84x⇒14280084=x⇒x=1700 Therefore, the marked price of the ring is Rs 1700. Page No 138:Question 11:After allowing a discount of 10% on the marked price, a trader still makes a gain of 17%. By what per cent is the marked price above the cost price? Answer:Let Rs 100 be the cost price. ⇒9x=1170 ⇒x=11709⇒x=130 ∴ Marked price = Rs 130 Hence, the marked price is 30% above the cost price. Page No 138:Question 12:How much per cent above the cost price should a shopkeeper mark his goods so that after allowing a discount of 10% on the marked price, he gains 8%? Answer:Let Rs 100 be the cost price. ⇒9x=1080⇒x=10809⇒x=120 ∴ Marked price = Rs 120 Hence, the marked price is 20% above the cost price. Page No 138:Question 13:The marked price of a TV is Rs 18500. A dealer allows two successive discounts of 20% and 5%. For how much is the TV available? Answer:Marked price of the TV = Rs 18500 Now, 20% of 18500=20100×18500=Rs 3700 Price after the first discount = Rs (18500
− 3700)= Rs 14800 Page No 138:Question 14:Find the single discount which is equivalent to two successive discounts of 20% and 5%. Answer:Let the marked price of the article be Rs 100. Page No 139:Question 1:The list price of a refrigerator is Rs 14650. If 6% is charged as sales tax, find the cost of the refrigerator. Answer:List price of the refrigerator = Rs 14650 Bill amount=Rs 14650+879 Page No 139:Question 2:Reena bought the following articles from a general store: Answer:(i) (ii) Cost of the medicines=Rs. 625 iii Cost of the cosmetics=Rs 430
Sales tax =10% of Rs 430 Hence, bill amount=Rs 430+43 iv Cost of clothes=Rs 1175 Sales tax=8% of Rs 1175
Page No 139:Question 3:Tanvy bought a watch for Rs 1980 including VAT at 10%. Find the original price of the watch. Answer:Let the original price of the watch be Rs x. Hence, the original price of the watch is Rs 1,800. Page No 139:Question 4:Mohit bought a shirt for Rs 1337.50 including VAT at 7%. Find the original price of the shirt. Answer:Let the original price of the shirt be Rs x. Hence, the original price of the shirt is Rs 1,250. Page No 139:Question 5:Karuna bought 10 g of gold for Rs 15756 including VAT at 1%. What is the rate of gold per 10 g? Answer:Let the price of 10 g of gold be Rs x. Hence, the price of 10 g of gold is Rs 15,600. Page No 139:Question 6:Mohini purchased a computer for Rs 37960 including VAT at 4%. What is the original price of the computer? Answer:Let the original price of the computer be Rs x. ∴ The original price of the computer is Rs 36,500 Page No 139:Question 7:Sajal purchased some car parts for Rs 20776 including VAT at 12%. What is the original cost of these spare parts? Answer:Let the original
cost of the spare parts be Rs x. Hence, the original cost of the spare parts is Rs 18,550. Page No 139:Question 8:The sale price of a TV set including VAT is Rs 27000. If the VAT is charged at 8% of the list price, what is the list price of the TV set? Answer:Let the list price of the TV set be Rs x. Hence, the list price of the TV set is Rs 25,000. Page No 139:Question 9:Rohit purchased a pair of shoes for Rs 882 inclusive of VAT. If the original cost be Rs 840, find the rate of VAT. Answer:Let the rate of VAT be x%. Then, we have: 840+x% of 840=882⇒x 100×840=882-840⇒84x10=42⇒x=42×1084 =5 ∴ The rate of VAT is 5%. Page No 139:Question 10:Malti bought a VCR for Rs 19980 including VAT. If the original price of VCR be Rs 18500, find the rate of VAT. Answer:Let the rate of VAT be x%. Then, we have: 18500+x% o f 18500=19980⇒x100×18500=19980-18500⇒185x=1480⇒x=1480185 =8 ∴ The rate of VAT is 8%. Page No 139:Question 11:The value of a car including VAT is Rs 382500. If the basic price of the car be Rs 340000, find the rate of VAT on cars. Answer:Let the rate of VAT be x%. Then, we have: 34000 +x% of 34000=382500⇒x100×340000=382500-340000⇒3400x=42500⇒x=425003400 =12.5 ∴ The rate of VAT is 12.5%. Page No 140:Question 1:Tick (✓) the correct answer: Answer:(c) 3313%SP=Rs 100Gain=Rs 100-75 =Rs 25∴ Gain percentage=gainCP×100% =2575×100% =3313% Page No 140:Question 2:Tick (✓) the correct answer: Answer:(b )1212%CP=Rs 120SP=Rs 105Loss=Rs 120-105 =Rs 15∴ Loss percentage=lossCP×100 =15120×100 =1212% Page No 140:Question 3:Tick (✓) the correct answer: Answer:(b) 25%CP=SP-Gain =Rs 100-20 =Rs 80∴ Gain percentage=gainCP×100% =2080×100% =25% Page No 140:Question 4:On selling an article for Rs 48, a shopkeeper loses
20%. In order to gain 20%, what would be the selling price? Answer:
(d) Rs 72SP=Rs 48Loss =20%Now, CP=100100-loss%×SP =Rs 100100 -loss%×SP =Rs 100100-20×48 =Rs 10080×48 =Rs 60 ∴ Desired SP=100+ gain%100×CP =100+20100×60=Rs 1210×60=Rs 72 Page No 140:Question 5:Tick (✓) the correct answer: Answer:(c) 120% Let the SP and CP of the article be Rs x and y, respectively. According to the question, we have: SP = Rs 2x =2x-10x11 10x11×100=1210×100=120% Page No 140:Question 6:Tick (✓) the correct answer: Answer:(d) 125% Page No 140:Question 7:Tick (✓) the correct answer: Answer:
(c) 20% Let Rs x be the SP
of each pen.SP of 10 pens=CP of 12 pens=Rs 12xCP of 10 pens=
Rs 10xNow, gain=Rs 12x-10x
=Rs 2x∴ Gain percentage=gainCP×100% Page No 140:Question 8:Tick (✓) the correct answer: Answer:
(b) 25% Let the SP of 100 pens be Rs x.SP of 1 pen=Rs x100Profit=Rs 20x100 =Rs x5Now, CP=x-x5 =4x5∴ Gain percentage=x54x5×100 =25% Page No 140:Question 9:Tick (✓) the correct answer: Answer:(d) 150% L.C.M of 5 and 2=5×1×2=10Let 10 be the number of toffees
bought.CP of 5 toffees=Rs 1 CP of 1 toffee=Rs 15∴
CP of 10 toffees=Rs 15×10
=Rs 2SP of 2 toffees= Rs 1SP of 1 toffee=
Rs 12∴ SP of 10 toffees=Rs 12×10 Page No 140:Question 10:Tick (✓) the correct answer: Answer:(d) 25% L.C.M of 5 and 6=5×1×6=30Let 30 be the number of oranges bought.CP of 5 oranges=Rs 10CP of 1 oranges=Rs 105 =Rs 2∴ CP of 30 oranges=Rs 2×30 =Rs 60SP of 6 oranges= Rs 15SP of 1 oranges=Rs 156 ∴ SP of 30 oranges=Rs 156×30 =Rs 75 Now, gain=Rs 75-60 =Rs 15∴ Gain percentage=gainCP×100% =1560×100% =25% Page No 140:Question 11:Tick (✓) the correct answer: Answer:(a) 4% SP of the radio=Rs 950Loss=5%CP=100100-loss ×SP =Rs 100100-5×950 =Rs 10095×950 =Rs 1000 Now, gain=Rs 1040-1000 =Rs 40∴ Gain percentage=gainCP×100% =401000×100% =4% Page No 140:Question 12:Tick (✓) the correct answer: Answer:(a) 20% Let Rs x be the CP of each article. SP of an article=Rs 65xNow, gain=SP-CP =Rs 65x-x =Rs x5∴ Gain percentage=gainCP×100% =x5x×100% = x5×1x×100% =20% Page No 140:Question 13:Tick (✓) the correct answer: Answer: (b) Rs.1200 SP=Rs 720Loss percentage=25
%CP=100100-loss%×SP =Rs 100100-25
×SP =Rs 10085×720 =Rs 960∴
Desired SP=100+gain%100×CP Page No 140:Question 14:Tick (✓) the correct answer: Answer:(a) 5% CP=Rs.20x SP=Rs.21xGain=Rs.21-20 =Rs.x∴ Gain percentage=gainCP×100% =x20x× 100% =5% Page No 140:Question 15:Tick (✓) the correct answer: Answer:(a) 1.5% gain SP of the first chair=Rs 500Gain
percentage=20%∴ CP of the first chair=100100+gain%×SP SP of the second chair=Rs.500Loss percentage=12%
∴ CP of the second chair=100100-loss%×SP Total CP of the two chairs=Rs.416.67+568.18 Page No 141:Question 16:Tick (✓) the correct answer: Answer:(b) Rs 530 Let the CP be Rs x. Then, we have:625-x=x-435⇒x+ x=625+435⇒2x=1060∴ x= Rs 530 Page No 141:Question 17:Tick (✓) the correct answer: Answer:(c) Rs 198 CP=Rs 150Total CP=Rs 150+10
% of 150 =Rs 150+10100×150
=Rs 150+15
=Rs 165∴ Desired SP=100+gain%100×total CP Page No 141:Question 18:Tick (✓) the correct answer: Answer:(a) Rs. 50 Let the CP be Rs x. Then, we have:105% of x-95% of x=5⇒105100×x-95100×x=5⇒105 x100-95x100=5⇒105x-95x100=5⇒10x100=5⇒x10=5⇒x=50∴ CP=Rs 50 Page No 141:Question 19:Tick
(✓) the correct answer: Answer:(b) 8% Let the CP be Rs 100.Then, marked price=Rs 120Discount=10% of MP =10% of Rs120=Rs.120×10100=Rs.12 Now, SP=MP-discount =Rs 120-12 =Rs 108Gain percentage= 108-100% =8% Page No 141:Question 20:Tick (✓) the correct answer: Answer:(c) 1% loss Let the CP be Rs 100.Then, marked price=Rs 110Discount=10% of MP
=10% of Rs.110=Rs.110×10100=Rs.11 Now, SP=MP-discount = Rs 110-11 =Rs 99∴ Loss percentage=(100 -99)%=1% Page No 141:Question 21:Tick (✓) the correct answer: Answer:(c) Rs.750 Let the
basic price be x.VAT=10% of Rs x =Rs x×
10100 =Rs x10∴ Price including VAT=Rs x+
x10 ∴ The basic price of the watch is Rs 750. Page No 142:Question 1:By selling a flower pot for Rs 322, a man gains 15%. At what price should he sell it to gain 20%? Answer:SP=Rs 322Gain percentage=15%∴ CP=100
100+gain%×SP ∴ The desired selling price is Rs 336. Page No 142:Question 2:If the cost price of 12 pens is equal to the selling price of 16 pens, find the loss per cent. Answer:Let the CP of each pen be Rs x.CP of 16 pens=Rs 16xSP of 16 pens=CP of 12 pens=Rs 12xi.e., CP>SPNow, loss=CP-SP =(16x-12x) =Rs.4x∴ Loss percentage= lossCP×100 =4x16x×100 =25% Page No 142:Question 3:A dealer gets Rs 30 less if instead of selling a chair at a gain of 12% he sells it at a gain of 8%. Find the cost price of the chair. Answer:Let the CP be
Rs x.Then, we have:12% of x-8% of x=30⇒x×12100-x×8100=30⇒12x100-8x100
=30⇒4x100=30⇒x=30×1004 =
750 Page No 142:Question 4:A trader marks his goods at 30% above cost price and allows a discount of 10%. What is his gain per cent? Answer:Let the CP be Rs 100.Then, marked price=Rs 130 Discount =10% of MP =10% of Rs.130=Rs.130×10 100=Rs.13 Now, SP=MP-discount =Rs.130-13
=Rs.117∴ Gain percentage=117-100%
=17% Page No 142:Question 5:Find the single discount equivalent to two successive discounts of 20% and 10%. Answer:Let the marked price
be Rs 100.Then, first discount on it =Rs 20Price after the first discount=
Rs 100-20 Price after the second discount=Rs.80-8 Page No 142:Question 6:Rajan bought a watch for Rs 1870 including VAT at 10%. Find the original price of the watch. Answer: Let the original price be Rs x.VAT=10% of Rs x
=Rs x×10100 =Rs x10
∴ Price including VAT=Rs x+x10 Page No 142:Question 7:Mark (✓) against the correct answer: Answer:(b) 25% Page No 142:Question 8:Mark (✓) against the correct answer: Answer:(d) 25% SP=Rs 100Gain=Rs 20CP=Rs 100-20 =Rs 80Gain percentage=gainCP×100% =2080 ×100% =25% Page No 142:Question 9:Mark (✓) against the correct answer: Answer:(b) 20% Let x be the CP of the article.Then , SP of the article=65xNow, gain=SP-CP = 65x-x =x5∴ Gain percentage=gain CP×100% =x5x×100% =x5×1x×100% =20% Page No 142:Question 10:Mark (✓) against the correct answer: Answer:(c) Rs.920
SP=Rs 680Loss percentage=15%Now, CP=100100-loss%×SP
Page No 142:Question 11:Mark
(✓) against the correct answer: Answer:(c) 8% Let the CP be Rs 100. Then, marked price=Rs 120 Discount=10% of MP =10% of Rs.120=Rs.120×10100=Rs.12 Now, SP=MP-discount =Rs 120-12 =Rs 108∴ Gain percentage=108-100 % =8% Page No 142:Question 12:Mark (✓) against the correct answer: Answer:(c) Rs.750 Let the original price be Rs x.VAT=8% of Rs x
=Rs x×8100 =Rs 8x100∴ Price including VAT=Rs x+8x100 Page No 142:Question 13:Fill in the blanks. Answer:(i) The discount is reckoned
on the marked price. Page No 142:Question 14:Write 'T' for true and 'F' for false for each of the following: Answer:(i) False (F) SP=100-loss%100×CP (ii) True (T) (iii) False (F) (iv) True (T) View NCERT Solutions for all chapters of Class 8 Is the cost price of 12 pens is equal to the selling price of 15 pencils then the loss percentage?Hence, the loss percent is 20%.
What is the profit if the cost price of 16 V is equal to selling price of 12 volt?PROFIT % = PROFIT/CP x 100 = 1/3 X 100 = 33.33%
Is the selling price of 10 pens is the same as the cost price of 12 pens then gain percentage?If the cost price of 12 pens is equal to selling price of 10 pens, what is the percentage of profit is: 16.67%
How do you find selling price when given cost and percentage?Cost price = Selling price + loss ( when selling price and loss is given ) Cost price =100×Selling Price100+Profit%( when selling price and profit % is given ) Cost price =100×Selling Price100−loss%( when selling price and loss % is given )
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